The time-period map
Let $H(p,q,t)$ be real analytic, $2\pi$-periodic in $t$, and satisfy $H_p(0,0,t)=H_q(0,0,t)=0$. The equations are $\dot p=-H_q$, $\dot q=H_p$. For a sufficiently small neighborhood of the origin, their time-$2\pi$ map $T$ is an analytic local diffeomorphism fixing the origin. The neighborhood may depend on the finite time interval under consideration. A solution with $T^nz=z$ closes after $2\pi n$ units of time; its least period may be smaller.
The suspended vector field on $(p,q,t\bmod2\pi)$ is $(-H_q,H_p,1)$. Its section $t=0$ identifies a periodically forced problem with a return-map problem. This is a local section, not a claim that every trajectory in the energy manifold crosses it.
Hamiltonian area preservation
Set $\omega=dq\wedge dp$. A two-form assigns an alternating bilinear quantity to two tangent vectors; here it is oriented area. The Hamiltonian vector field $X_t$ satisfies $\iota_{X_t}\omega=d_{p,q}H$. Here $\iota_X\omega$ means the one-form $v\mapsto\omega(X,v)$, and $d_{p,q}$ differentiates only in the state variables. Therefore
$$\mathcal L_{X_t}\omega=d(\iota_{X_t}\omega)+\iota_{X_t}d\omega=d^2H=0.$$
The Lie derivative $\mathcal L_X$ measures the infinitesimal change of a form along a flow. Thus the flow, and in particular $T$, preserves $\omega$. This is the differential-form version of Birkhoff’s incompressible-tube calculation. In coordinates it is simply
$$\operatorname{div}(-H_q,H_p)=-H_{qp}+H_{pq}=0,\qquad\det DT=1.$$
A noncanonical change of variables can change the coordinate area element. What survives is a smooth positive invariant density, sufficient for the intersection argument below.
The finite normal-form input
An elliptic fixed point has linear eigenvalues $e^{\pm i\sigma}$ on the unit circle. Assume $\sigma/(2\pi)$ is irrational and that the first twist coefficient $s$ is nonzero. The finite-order normal-form input from Birkhoff’s earlier chapters gives, after a local analytic change of coordinates,
$$\rho_1=\rho+O(\rho^{\mu+1}),\qquad\theta_1=\theta+\sigma+s\rho+O(\rho^\mu),\qquad\rho=r^2,$$
with differentiated remainder estimates as in §2. The normalization is to arbitrarily high finite order; it does not assert convergence of an infinite normalizing series. Reverse the angular orientation if needed to take $s>0$.
Ellipticity alone is insufficient. The condition $s\ne0$ produces a radial variation of rotation, while area preservation prevents the resonant curve from escaping its image. This argument does not assert nonlinear stability solely from irrational linear eigenvalues.
Resonant curves and intersections
Lemma input. For arbitrarily small $\varepsilon>0$, choose an integer $n$ so that all iterates through $n$ stay in $r<2\varepsilon$, and the lifted angular displacement
$$D_n(r,\theta)=\theta_n(r,\theta)-\theta$$
strictly increases with $r>0$, from $n\sigma$ at $r=0$ to more than $n\sigma+2\pi$ at $r=\varepsilon$. Section 2 supplies these finite-time estimates.
Let $k$ be the smallest integer with $2\pi k>n\sigma$. Irrationality makes this inequality strict. On each ray there is exactly one solution of $D_n(r,\theta)=2\pi k$. The implicit-function theorem gives a closed radial graph $C:r=R(\theta)>0$. Every point of $C$ is carried by $T^n$ to the same ray.
Proposition. The curves $C$ and $T^nC$ intersect, and every intersection yields a fixed point of $T^n$ on $C$.
Proof. Both curves are simple and surround the origin. If disjoint, one bounds a disk strictly contained in the other. The intervening open annulus has positive measure for the smooth invariant density. This contradicts equality of the two disk measures under $T^n$. Choose $Q=T^nP\in C\cap T^nC$, with $P\in C$. The angular equation puts $P,Q$ on the same ray. A radial graph has only one point on a ray, so $P=Q$. ∎
The resulting nonzero periodic points approach the origin as $\varepsilon\to0$. A finite collection of periodic orbits cannot do this, since each has finitely many nonzero points. Hence there are infinitely many distinct periodic orbits near the origin. Their periods are unbounded: for each fixed $n$, $DT^n(0)-I$ is invertible by nonresonance, so the origin is an isolated zero of $T^n-I$.